First slide

Fluid dynamics

Question

An incompressible fluid flows steadily through a cylindrical pipe which has radius 2r at point A and radius r at B further along the flow direction. If the velocity at point A is v, its velocity at point B is

Easy

A

2v
B

v
C

v/2
D

4v

Solution

$A_{1} v_{1} = A_{2} v_{2} π {(2 r)}^{2} v = {πr}^{2} v_{2} v_{2} = 4 v$

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