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Q.

Increase in length of a wire is 1 mm when suspended by a weight. If the same weight is suspended on a wire of double its length and double its radius, the increase in length will be

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a

2 mm

b

0.5 mm

c

4 mm

d

0.25 mm

answer is B.

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Detailed Solution

l=FLAY⇒l∝Lr2(F and Y are same )∴l2l1=L2L1r1r22=2×122=12⇒l2=l12=l2=0.5mm
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