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Q.

Increase in length of a wire on stretching is 0.025%. If its poisson's ratio is 0.4, percentage decrease in diameter is:

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a

0.03%

b

0.02%

c

0.01%

d

0.05%

answer is C.

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Detailed Solution

∆ll=0.025100=2.5×10-4 -∆DD=σ×∆ll=0.4×2.5×10-4=10-4 -∆DD×100=0.01%
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