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Q.

On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross-section 2 mm2, the force required is [Y for steel = 2.2× 1011 N/m2]

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a

1.1 × 105 N

b

1.1 × 104 N

c

1.1 × 103 N

d

1.1 × 102 N

answer is D.

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Detailed Solution

Y = FIA∆l or F = YA∆llor F = 2.2×1011×2×10-6×0.5×10-32 = 1.1 × 102 N
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