An Indian rubber cord L metre long and area of cross-section A metre2 is suspended vertically. Density of rubber is p kg/metre3 and Young's modulus of rubber is Y newton/metre2. If the cord extends by l metre under its own weight, then extension I is
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a
L2ρg/Y
b
L2ρg/2Y
c
L2ρg/4Y
d
Y/L2ρg
answer is B.
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Detailed Solution
Weight of the cordW=Vρg=ALρg∴ Stress =WA=LρgFor the purpose of extension, the weight acts at the centre of gravity of the bar. Hence the upper half length, i.e., [L / 2) will be stretched.∴ Strain =l(L/2)=2lLNow, Y= Stress Strain =Lρg×L2l=L2ρg2lor l=L2ρg/2Y