Questions
The inductance of a closed-packed coil of 400 turns is 8 mH. A current of 5 mA is passed through it. The magnetic flux through each turn of the coil is
detailed solution
Correct option is A
Nϕ=Li⇒ϕ=LiN=8×10-3×5×10-3400=10-7=μ04πWbTalk to our academic expert!
Similar Questions
Fig.(6) represents an area A = 0.5m2 situated in a
uniform magnetic field B = 2.0weber/m2 and making an angle of 60o with respect to magnetic field. The value of the magnetic flux through the area would be equal to
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