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An inductance of 0.2H and resistance 100Ω  are connected to an AC 180V – 50Hz. The current in the circuit is

a
0.52 A
b
5.2 A
c
1.52 A
d
15.2 A

detailed solution

Correct option is C

ω=2πn=2π×50=314rad/sec V rms =180 volt  Resistance =R=100 ohm, Inductance=L=0.2 Hi=VR2+(Lω)2 =.1801002+0.2x3142=1.52A

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