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In an induction coil the coefficient of mutual inductance is 4H. If current of 5A in the primary coil is cut off in 11500 seconds, the emf at the terminals of secondary coil is 

a
15 KV
b
30 KV
c
10 KV
d
60 KV

detailed solution

Correct option is B

ε21=-Mdi1dt=4×51/1500volt=30 KV

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