Story
NEET AITS
Story
Mock Tests
Story
Live Class
Story
JEE AITS

Questions  

An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watt when a current of 4 amp is passed through it. Find the time constant of the circuit when the coil is joined  across a battery.

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
0.2 sec
b
0.1 sec
c
0.3 sec
d
0.4 sec

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is A

U=12LI2    ;  32=12×L×42  ∴L=4Hand I2R=320⇒(4)2 R=320 ∴ R=20ΩT=L/R=420=0.2 sec

ctaimg

Similar Questions

A loop, having area 20cm2, is made of thin copper wire. If is placed in a uniform magnetic field of induction 1.5 Tesla with its plane perpendicular to the field. If area of the loop increases to 30 cm2 in 0.5 second, average emf induced in the loop is

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon