An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watt when a current of 4 amp is passed through it. Find the time constant of the circuit when the coil is joined across a battery.

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answer is A.

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Detailed Solution

U=12LI2 ; 32=12×L×42 ∴L=4Hand I2R=320⇒(4)2 R=320 ∴ R=20ΩT=L/R=420=0.2 sec

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