Questions
Induction of a solenoid is 15 mH. Now length of the solenoid is halved, number of turns doubled and area of cross section remains the same. Then the new inductance of the solenoid will be
detailed solution
Correct option is B
L=μ0n2×lA=μ0(Nl)2×lA=μ0N2Al∴ L1L=(N1N)2×(ll1)=(2)2×(2)=8⇒L1=120 mHTalk to our academic expert!
Similar Questions
A coil is wound as a transformer of rectangular cross-section. If all the linear dimensions of the transformer are increased by a factor 2 and the number of turns per unit length of the coil remain the same, the self inductance increased by a factor of
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