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Phasors and Phasor Diagrams

Question

An inductor and a capacitor are connected in series and altering source V=1202cos100πtvolt  is connected across the combination. The rms current in the circuit is found to be 5 A. When a resistor of resistance R is connected in series with the inductor and capacitor and the same alternating source is used, the rms current in the circuit is found to be 4 A, Then the value of R is

Difficult
Solution

Let I1 and v be rms values of current and voltge of LC AC circuit

I1=vz1=vXLXCXLXC=vI1

I2=vz2=vR2+XLXC2R2=v2I22XLXC2=v2I22v2I12

R=vI12-I22I1I2=120×52425×4Ω=18Ω



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