Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

An inductor and a capacitor are connected in series and altering source V=1202cos100πt volt  is connected across the combination. The rms current in the circuit is found to be 5 A. When a resistor of resistance R is connected in series with the inductor and capacitor and the same alternating source is used, the rms current in the circuit is found to be 4 A, Then the value of R is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 3.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let I1 and v be rms values of current and voltge of LC AC circuitI1=vz1=vXL−XC⇒XL−XC=vI1I2=vz2=vR2+XL−XC2⇒R2=v2I22−XL−XC2=v2I22−v2I12∴R=vI12-I22I1I2=120×52−425×4Ω=18Ω
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon