First slide
Inductance
Question

An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 320 W when a current of 4 amp is passed through it. Find the time constant of the circuit when it is formed across an ideal battery.

Difficult
Solution

Magnetic field energy stored=U=12Li2

32=12L(4)2 or L=4 Henry 

 Power dissipated as heat is P=i2R

320=42R or R=20ohm

 Time constant of circuit =τ=LR=420=0.2sec

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