Q.

An inductor coil stores 32 J of magnetic field energy and dissipates energy as heat at the rate of 320 W when a current of 4 amp is passed through it. Find the time constant of the circuit when it is formed across an ideal battery.

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a

τ=0.2sec

b

τ=0.32sec

c

τ=0.5sec

d

τ=1sec

answer is A.

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Detailed Solution

Magnetic field energy stored=U=12Li232=12L(4)2 or L=4 Henry  Power dissipated as heat is P=i2R320=42R or R=20ohm Time constant of circuit =τ=LR=420=0.2sec
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