An inductor having self inductance L and resistance R is connected across a battery of emf ε. When the current is in steady state, at t = 0 an iron rod is inserted into the inductor. Then after insertion of the rod, current in the circuit
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a
increases with time
b
decreases with time
c
remains constant with time
d
first decreases with time then becomes constant
answer is D.
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Detailed Solution
When the iron rod is inserted, inductance of coil is changed abruptly, flux in it remains same i.e. ϕ=Li=constant, so current will decrease. Now current will increase with time to attain the steady value εR.