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An inductor of 5 henry and a resistance of 10 ohms are connected in series with a battery of 15 volts. The initial rate of change of current is    

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a
3.5 amp/sec
b
2.0 amp/sec
c
3.0 amp/sec
d
0.25 amp/sec

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detailed solution

Correct option is C

i=i01−e−RtL⇒didt=ddti0−ddti0e−RtL⇒didt=0−i0−RL e−RtL=i0RLe−RtLInitially,     t=0⇒didt=i0×RL=EL=155=3 amp/sec.

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