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Q.

An inductor of 5 henry and a resistance of 10 ohms are connected in series with a battery of 15 volts. The initial rate of change of current is

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a

3.5 amp/sec

b

2.0 amp/sec

c

3.0 amp/sec

d

0.25 amp/sec

answer is C.

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Detailed Solution

i=i01−e−RtL⇒didt=ddti0−ddti0e−RtL⇒didt=0−i0−RL e−RtL=i0RLe−RtLInitially,     t=0⇒didt=i0×RL=EL=155=3 amp/sec.
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