An inductor of 5 henry and a resistance of 10 ohms are connected in series with a battery of 15 volts. The initial rate of change of current is
3.5 amp/sec
2.0 amp/sec
3.0 amp/sec
0.25 amp/sec
i=i01−e−RtL⇒didt=ddti0−ddti0e−RtL
⇒didt=0−i0−RL e−RtL=i0RLe−RtL
Initially, t=0⇒didt=i0×RL=EL=155=3 amp/sec.