First slide

Electrical machines and devices

Question

In an inductor of inductance L = 100 mH, a current of I=10 A is flowing. The energy stored in the inductor is

Moderate

A

5 J
B

10 J
C

100 J
D

1000 J

Solution

$U = \frac{1}{2} {Li}^{2} = \frac{1}{2} \times 100 \times 10^{- 3} \times {(10)}^{2} = 5 J$

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