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Q.

In an inductor of inductance L = 100 mH, a current of  I=10 A is flowing. The energy stored in the inductor is

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a

5 J

b

10 J

c

100 J

d

1000 J

answer is A.

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Detailed Solution

U=12Li2=12×100×10−3×(10)2=5J
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