An inductor of inductance ‘L’ in series with resistance R is connected to an ideal battery of emf V0 at t = 0. The maximum power developed across the inductor during growth of current is
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a
V02R
b
V024R
c
V023R
d
Zero
answer is B.
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Detailed Solution
i2R+P=V0i i2R-V0i+P=0 For i to be real V02≥4PR ∴ Pmax=V024R