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Questions  

An inductor of inductance 1000mH is connected in series with a resistance, a variable capacitance and an AC source of frequency 5 kHz. The value of the capacitance so that maximum current may be drawn into the circuit

a
2 nF
b
1 nF
c
4 nF
d
8 nF

detailed solution

Correct option is B

At  resonance  maximum current will be drawn by the circuit. Then xL=xC  i.e   fr=12πLC ⇒C=14π2f2L=14×10×(5×103)2×1=1×10−9=1nF .

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