An inductor $$20mH$$,a capacitor $$50$$μF and a resistor $$40$$Ω are connected in series across a source of emf $$V=10sin$$⁡ $$340t$$.The power loss in A.C. circuit is

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An inductor $$20mH$$,a capacitor $$50$$μF and a resistor $$40$$Ω are connected in series across a source of emf $$V=10sin$$⁡ $$340t$$.The power loss in A.C. circuit is

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Here, $$L=20mH=20$$×$$10-3H$$,$$C=50$$μ$$F=50$$×$$10-6$$ $$FR=40$$Ω,$$V=10sin340t=V0sin$$ωtω$$=340rads-1$$,$$V0=10$$ $$VXL=$$ω$$L=340$$×$$20$$×$$10-3=6.8$$Ω$$XC=1$$ω$$C=1340$$×$$50$$×$$10-6=10434$$×$$5=58.82$$Ω$$Z=R2+XC-XL2=(40)2+(58.82-6.8)2=(40)2+(52.02)2=65.62$$ΩThe peak current in the circuit is $$I0=V0Z=1065.62$$ A,$$cos$$ϕ$$=RZ=4065.62Power$$ loss in A.C. circuit $$=VrmsIrmscos$$ϕ$$=12V0I0cos$$ϕ$$=12$$×$$10$$×$$1065.62$$×$$4065.62=0.46$$ W

An inductor $20 m H,$ a capacitor $50 μ F$ and a resistor $40 Ω$ are connected in series across a source of emf $V = 10 \sin 340 t .$ The power loss in A.C. circuit is

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An inductor 20mH,a capacitor 50μF and a resistor 40Ω are connected in series across a source of emf V=10sin⁡ 340t.The power loss in A.C. circuit is

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An inductor $20 m H,$ a capacitor $50 μ F$ and a resistor $40 Ω$ are connected in series across a source of emf $V = 10 \sin 340 t .$ The power loss in A.C. circuit is