Questions
An inductor 20 mH, a capacitor 100 and a resistor 50 are connected in series across a source of emf, V=10 sin 314 t. The power loss in the circuit is
detailed solution
Correct option is A
Impedance Z in an ac circuit isZ=R2+XC-XL2; where XC= capacitive reactance and XL= inductive reactance. Also XC=1ωC and XL=ωL∴Z=(50)2+1314×100×10-6-314×20×10-32 or Z=56Ω The power loss in the circuit is Pav=VrmsZ2R∴Pav=10(2)562×50=0.79 WTalk to our academic expert!
Similar Questions
An LCR series circuit with a resistance of 100 ohm is connected to an ac source of 200 V (r.m.s.) and angular frequency 300 rad/s. When only the capacitor is removed, the current lags behind the voltage by 60o . When only the inductor is removed the current leads the voltage by 60o . The average power dissipated is
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