Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

An inductor and two capacitors are connected in the circuit as shown in figure. Initially capacitor A has no charge and capacitor B has CV charge. Assume that the circuit has no resistance at all. at at=0, switch S is closed, then [given LC=2π2×104s2 and CV=100mC ]choose the correct option

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

When current in the circuit is maximum, charge on  capacitor A is thrice the charge on capacitor B

b

When current in the circuit is maximum, charge on capacitor A is twice the charge on capacitor B

c

q=50(1+cos100πt)mC , where q is the charge on capacitor B at time t

d

q=50(1−cos100πt)mC , where q is the charge on capacitor B at time t

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Ld2qdt2+qC−CV−qC=0  BY applying kirchoffs lawd2qdt2+2q−CVLC=0ω=2LC=22π2×104=100πq=CV2[1−cosωt]q'=CV−q=CV2[1+cosωt]=1002[1+cos100πt]=50[1+cos100πt]I=+CVω2sinωt
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon