An infinite sheet of charge has a surface charge density of 8.85×10−7C/m2. The separationbetween two equipotential surfaces, whose potentials differ by 10 V is

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0.2 mm

2 mm

2 cm

20 cm

answer is A.

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Detailed Solution

ΔV=EΔr⇒10=σ2ε0×Δr⇒Δr=20×8.85×10−128.85×10−7=0.2mm