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Q.

An infinitely long conductor POR is bent to form a right angle as shown in figure. A current i flows through POR. The magnetic field due to this current carrying conductor at the point M is B1. Now, another infinitely long straight conductor QS, is connected at Q so that the current is i/ 2  in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now B2. The ratio B1/B2 is given by

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a

1/2

b

1

c

2/3

d

2

answer is C.

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Detailed Solution

B→1=μ0I4πR⊙, B→2=μ0I4πR+μ0I/24πR⊙ ⇒ B2=μ0I4πR32⊙ ⇒B1B2=23
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An infinitely long conductor POR is bent to form a right angle as shown in figure. A current i flows through POR. The magnetic field due to this current carrying conductor at the point M is B1. Now, another infinitely long straight conductor QS, is connected at Q so that the current is i/ 2  in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now B2. The ratio B1/B2 is given by