An infinitely long conductor PQR is bent to form a right angle as shown. A current f flows through PQR. The magnetic field due to this current at the point M is $$H1$$. Now another infinitely long straight conductor QS is connected at Q so that the current is $$I/2$$ in QR as well as in QS. The current in PQ remains unchanged. The magnetic field at M is now $$H2$$. The ratio $$H1/H2$$ is given by

Question

An infinitely long conductor PQR is bent to form a right angle as shown. A current f flows through PQR. The magnetic field due to this current at the point M is $$H1$$.  Now another infinitely long straight conductor QS is connected at Q so that the current is $$I/2$$ in QR as well as in QS. The current in PQ remains unchanged. The magnetic field at M is now $$H2$$. The ratio $$H1/H2$$ is given by

Infinity Learn · Accepted Answer

Magnetic field at any point lying on the axis of a current carrying straight conductor is zero.Here $$H1$$ $$=$$ Magnetic field at M due to current in PQ.$$=$$ μ$$0I4$$$$π$$$$rH2$$ $$=$$ Magnetic field at M due to $$QR+$$ magnetic field at M due to $$QS+$$ magnetic field at M due to $$PQ=$$ $$0$$ $$+$$μ$$0I/24$$$$π$$$$r+$$μ$$0I4$$$$π$$$$r=32$$μ$$0I4$$$$π$$r.    Therefore $$H1H2=23$$

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