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Q.

An infinitely long conductor PQR is bent to form a right angle as shown. A current f flows through PQR. The magnetic field due to this current at the point M is H1. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS. The current in PQ remains unchanged. The magnetic field at M is now H2. The ratio H1/H2 is given by

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a

12

b

1

c

23

d

2

answer is C.

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Detailed Solution

Magnetic field at any point lying on the axis of a current carrying straight conductor is zero.Here H1 = Magnetic field at M due to current in PQ.= μ0I4πrH2 = Magnetic field at M due to QR+ magnetic field at M due to QS+ magnetic field at M due to PQ= 0 +μ0I/24πr+μ0I4πr=32μ0I4πr. Therefore H1H2=23

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