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Q.

An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field due to this current at the point M is H1. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now H2. The ratio H1/H2  is given by

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a

b

1

c

d

2

answer is C.

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Detailed Solution

Magnetic field at any point lying on the current carrying straight conductor is zero.Here H1 = Magnetic field at M due to current in PQ.        H2 = Magnetic field at M due to QR                + magnetic field at M due to QS                + magnetic field at M due to PQ
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An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field due to this current at the point M is H1. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now H2. The ratio H1/H2  is given by