Q.
An infinitely long straight wire PQ, carrying a current of 10 A lies in the plane of a square loop ABCD as shown in the figure. The loop is made to move with a constant velocity of 1m/s away from the wire PQ. Then the emf induced in the loop, at the instant shown in figure, is
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a
10-6 volt
b
10-5 volt
c
10-4 volt
d
10-3 volt
answer is A.
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Detailed Solution
Net emf = Emf induced in AD - Emf induced in BC =μ0 x 102π x 1 x 1 x 1-μ0 x 102π x 2x 1 x 1 volt=5μ02π volt=5 x 4π x 10-72π volt=10-6 volt
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