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Q.

An infinitely long straight wire PQ, carrying a current of 10 A lies in the plane of a square loop ABCD as shown in the figure. The loop is made to move with a constant velocity of 1m/s away from the wire PQ. Then the emf induced in the loop, at the instant shown in figure, is

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a

10-6 volt

b

10-5 volt

c

10-4 volt

d

10-3 volt

answer is A.

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Detailed Solution

Net emf = Emf induced in AD - Emf induced in BC =μ0 x 102π x 1 x 1 x 1-μ0 x 102π x 2x 1 x 1 volt=5μ02π volt=5 x 4π x 10-72π volt=10-6 volt
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