Q.
At the initial moment three points A, B and C are on a horizontal straight line at equal distances from one another. Point A begins to move vertically upward with a constant velocity and point C vertically downward without any initial velocity but with a constant acceleration a. How should point B move vertically for all the three points to be constantly on one straight line. The points begin to move simultaneously.
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answer is 1.
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Detailed Solution
Let AB=BC=dBD=xand BB'=s= displacement of point B.From similar triangles we can write,vtd+x=sx=12at2d-xFrom first two equations we have,1+dx=vts or dx=vts-1.....(i)From last two equations we have,dx-1=12at2s dx=12at2s+1.....(ii)Equating Eqs. (i) and (ii), we havevts-1=12at2s+1orvt-12at2s=2 ∴s=v2t-12a2t2Comparing with s=ut+12at2 we have, Initial velocity of B is +v2 and acceleration -a2
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