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Q.

Initial number of active nuclei in a sample of radioactive element is 2000, half life of the element is 500 s. At an instant of time, rate of disintegration is found to be 2s-1 . Then number of nuclei decayed upto that instant of time is, (Given ln2=0.693, 10000.693=1443)

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a

557

b

321

c

879

d

1440

answer is A.

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Detailed Solution

T = Half life =ln2λ⇒1λ=Tln2Now Activity, A=λN∴N=Aλ=ATln2=2 x 5000.693=1443∴Number of nuclei decayed = 2000 - 1443 = 557
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