The initial temperature of a body is 800C. If its temperature falls to 640C in 5 minutes and in next 10 minutes to 520. Find the temperature of surrounding.
260C
600C
360C
490C
According to Newton's law θ1-θ2t = k[θ1+θ22-θ0]
Initially, (80-64)5 = K(80+642-θ0)
⇒3.2 = K[72-θ0]-------(i)
Finally, (64-52)10 = K[64+522-θ0]
⇒ 1.2 = K[58-θ0]------(ii)
On solving equation (i) and (ii) θ0 = 490C