The initial velocity of a particle of mass 2 kg is (4i^+4j^)ms-1 A constant force of -20j^N is applied on the particle. Initially, the particle was at (0, 0). Find the x-coordinate of the point, where its y-coordinate is again zero.
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a
3.2 m
b
6 m
c
4.8 m
d
1.2 m
answer is A.
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Detailed Solution
We can see that it is like a projectile motion, withux=4 ms-1,uy=4 ms-1 and ay=10 ms-2x-coordinate = Range =2uxuyg=2×4×410=3.2 m