Q.
The initial velocity of a particle is u=(4i^+3j^) ms-1. It is moving with uniform acceleration a=(0.4i^+0.3j^) ms−2. The magnitude of its velocity after 10 s is
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a
3 ms-1
b
4 ms-1
c
5 ms-1
d
10 ms-1
answer is D.
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Detailed Solution
v=u+at =(4i^+3j^)+(0.4i^+0.3j^)×10 =(8i^+6j^) ms−1The x and y components of velocity are vx = 8 ms-1 and vy= 6 ms-1. The magnitude of velocity v=vx2+vy2=(8)2+(6)2=10 ms−1
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