Initially a gas of diatomic molecules is contained in a cylinder of volume $$V1$$ at a pressure $$P1$$ and temperature $$250$$ K. Assuming that $$25$$% of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature $$2000$$ K, when contained in a volume $$2V1$$ is given by $$P2$$. The ratio $$P2/P1$$ is ……

Question

Initially a gas of diatomic molecules is contained in a cylinder of volume  $$V1$$ at a pressure $$P1$$ and temperature $$250$$ K. Assuming that $$25$$% of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature $$2000$$ K, when contained in a volume $$2V1$$ is given by  $$P2$$. The ratio $$P2/P1$$  is ……

Infinity Learn · Accepted Answer

Applying PV $$=$$  $$nRTP1V1=nR250New$$ moles $$=$$ $$(75$$% of n $$)+$$ $$(2)(25$$% of $$n)=1.25nSo$$, $$P22V1=1.25$$  $$nR2000$$∴Ratio $$=P2P1=5$$

Thermodynamic processes

Remember concepts with our Masterclasses.

$A p p l y i n g P V = n R T$
$P_{1} V_{1} = n R (250)$
$N e w m o l e s = (75 % o f n) + (2) (25 % o f n) = 1.25 n$
$S o, P_{2} (2 V_{1}) = 1.25 n R (2000)$
$∴ R a t i o = \frac{P_{2}}{P_{1}} = 5$

Ready to Test Your Skills?

free study material

Thermodynamic processes

Remember concepts with our Masterclasses.

Applying PV = nRTP1V1=nR250New moles = (75% of n )+ (2)(25% of n)=1.25nSo, P22V1=1.25 nR2000∴Ratio =P2P1=5

Ready to Test Your Skills?

free study material

$A p p l y i n g P V = n R T$
$P_{1} V_{1} = n R (250)$
$N e w m o l e s = (75 % o f n) + (2) (25 % o f n) = 1.25 n$
$S o, P_{2} (2 V_{1}) = 1.25 n R (2000)$
$∴ R a t i o = \frac{P_{2}}{P_{1}} = 5$