First slide

Thermal expansion

Question

The inner diameter of a brass ring at 273 K is 5 cm. To what temperature should it be heated for it to accommodate a ball 5.01 cm in diameter. ( $α$ = 2 × 10^-5 /°C)

Moderate

A

273 K
B

372 K
C

437 K
D

173 K

Solution

$Δt = \frac{r_{2} - r_{1}}{r_{1} α}$

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