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The inner diameter of a brass ring at 273 K is 5 cm. To what temperature should it be heated for it to accommodate a ball 5.01 cm in diameter. (α = 2 × 10-5 /°C)

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An Intiative by Sri Chaitanya

a

273 K

b

372 K

c

437 K

d

173 K

answer is B.

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Δt=r2−r1r1α

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