The input resistance of a common emitter transistor amplifier, if the output resistance is 500 kΩ, the current gain α = 0.98 and power gain is 6.0625 x 106, is

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100 Ω

300 Ω

198 Ω

400 Ω

answer is C.

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Detailed Solution

Voltage gain, Av=βR2R1Also, current gain, β=α1−α=0.981−0.98=49Av=49500×103R1Power gain=6.0625×106=49×500×103R1×49∴R1=198 Ω

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