An insect is at the bottom of a hemispherical ditch of radius $$1m$$. It crawls up the ditch but starts slipping after it is at height ‘h’ from the bottom. If the coefficient of friction between the ground and the insect is $$0.75$$, then ‘h’ is: $$g=10$$ ms−$$2$$

Question

An insect is at the bottom of a hemispherical ditch of radius $$1m$$. It crawls up the ditch but starts slipping after it is at height ‘h’ from the bottom. If the coefficient of friction between the ground and the insect is $$0.75$$, then ‘h’ is:  $$g=10$$  ms−$$2$$

Infinity Learn · Accepted Answer

At a point where slipping just starts, ​$$f=mg$$  $$sin$$θ      ​⇒ μmgcosθ$$=mg$$  $$sin$$θ​⇒$$tan$$θ $$=$$ μ​as  μ$$=0.75$$,   θ$$=370$$               ​ ∴$$h=R1$$−$$cos$$θ$$=0.20$$  m

An insect is at the bottom of a hemispherical ditch of radius 1m. It crawls up the ditch but starts slipping after it is at height ‘h’ from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then ‘h’ is: $(g = 10 m s^{- 2})$

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An insect is at the bottom of a hemispherical ditch of radius 1m. It crawls up the ditch but starts slipping after it is at height ‘h’ from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then ‘h’ is: g=10 ms−2

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

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An insect is at the bottom of a hemispherical ditch of radius 1m. It crawls up the ditch but starts slipping after it is at height ‘h’ from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then ‘h’ is: $(g = 10 m s^{- 2})$