An insect crawling up a fixed hemispherical bowl of radius .R. If the coefficient of friction is 13, then the insect can only crawl upto a height of
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a
0.051 R
b
0.51 R
c
0.0051 R
d
0.95 R
answer is A.
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Detailed Solution
See fig.The insect will crawl up the bowl till the component of its weight down the plane just equals the force of limiting frictionF=Wsinα and N=Wcosαμ=tanα=F/N=1/3 But tanπ2−α=cot α=xR2−x2 so that X=3/10=0⋅949RNow h=R−x=0⋅051R.