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Q.

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t3 -6t2. The torque on the wheel becomes zero at [CBSE AIPMT 2011]

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a

t = 0.5 s

b

t = 0.25 s

c

t = 2 s

d

t = 1 s

answer is D.

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Detailed Solution

According to question,torque,  τ=Iα=0⇒ α=0 or  α=d2θdt2=0Given,  θ(t)=2t3−6t2So,  dθdt=6t2−12t⇒ d2θdt=12t−12   ∵α=d2θdt2=012t−12=0⇒t=1s
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