First slide
Electrostatic force
Question

An insulating long light rod of length L pivoted at its centre O and balanced with a weight W at a distance X from the left end as shown in figure. Charges q and 2q are fixed to the ends of the rod. Exactly below each of these charges at a distance h a positive charge Q is fixed. Then x is

 

Difficult
Solution

By law of conservation of Moments about C,
Total Clockwise CWMoments=Total counter Clockwise CCW      Moments qQ4πε0h2L2+Wx-L2=2qQ4πε0h2L2  Wx-L2=QqL8πε0h2x=QqL+4πε0h2LW8πε0h2W

 


 

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