Questions
An insulating rod of length L carries a charge ‘q’ distributed uniformly on it. The rod is pivoted at its mid point and is rotated at a frequency f about a fixed axis perpendicular to the rod and passing through the pivot. The magnetic moment of the rod system is
detailed solution
Correct option is A
At a distance ‘x’ consider a small element of width ‘dx’ .As the element rotates, it can be considered as a current carrying loop.Magnetic moment of the small element is dM=IA=dqTπx2=qldx fπx2⇒M=qfπl∫−l/2l/2x2dx=qπfl212 .Talk to our academic expert!
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The figure below shows the north and south poles of a permanent magnet in which n turn coil of area of cross-section A is resting, such that for a current i passed through the coil, the plane of the coil makes an angle with respect to the direction of magnetic field B. The couple acting on the coil is
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