First slide

Law of equipartition of energy

Question

An insulator container contains 4 moles of an ideal diatomic gas at temperature T. Heat Q is supplied to this gas, due to which 2 moles of the gas are dissociated into atoms but temperature of the gas remains constant. Then

Moderate

A

$Q = 2 RT$
B

$Q = RT$
C

Q = 3RT
D

Q = 4RT

Solution

$Q = ∆ U = U_{f} - U_{i} = [[intemal energy of 4 moles of a monoatomic gas + internal energy of 2 moles of a diatomic gas]$
$- [intemal energy of 4 moles of a diatomic gas]$
= $(4× \frac{3}{2} RT + 2 \times \frac{5}{2} RT) - (4 \times \frac{5}{2} RT) = RT$

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