First slide

Change in internal energy

Question

An insulator container contains 4 moles of an ideal diatomic gas at temperature T. Heat Q is supplied to the gas, due to which 2 moles of the gas are dissociated into atoms but temperature of the gas remains constant.

Easy

A

Q = 2RT
B

Q = RT
C

Q = 3RT
D

Q = 4RT

Solution

$Q = ΔU = U_{f} - U_{i}$ = ( internal energy of 4 moles of a monoatomic gas + internal energy of the 2 moles of diatomic gas) – ( internal energy of 4 moles of diatomic ideal gas) = $(4× \frac{3 RT}{2} + 2 \times \frac{5}{2} RT) - (4 \times \frac{5}{2} RT) = RT$

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