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Q.

Integrate the following : ∫(2t−4)−4dt=

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a

−(2t−4)−36+C

b

(2t−4)36+C

c

(2t−4)32+C

d

(2t−4)−32+C

answer is A.

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Detailed Solution

u=2t−4∫u−4du2=−12u−33+C
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