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Integration
Question
Integrate :
∫
3
2
x
d
x
Easy
A
x
3
+
C
B
x
+
C
C
x
+
C
D
1
x
+
C
Solution
∫
3
2
x
d
x
=
3
2
x
3
/
2
3
/
2
+
C
=
x
3
+
C
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