First slide

Young's double slit Experiment

Question

Intensities of the two waves of light are I and 4I. The maximum intensity of the resultant wave after superposition is

Easy

A

5 I
B

9 I
C

16 I
D

25 I

Solution

$I_{max} = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}}$
So, $I_{max} = I + 4 I + 2 \sqrt{I . 4 I} = 9 I$

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