Q.
The intensity of the electric field required to keep a water drop of radius 10−5 cm just suspended in air when charged with one electron is approximately g=10 newton /kg,e=1.6×10−19 coulomb
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a
260 volt /cm
b
260 newton/coulomb
c
130 volt /cm
d
130 newton/coulomb
answer is B.
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Detailed Solution
For balance mg=eE⇒E=mgeAlso m=43πr3d=43×227×10−73×1000kg⇒E=4/3×22/7×10−73×1000×101.6×10−19=260 N/C
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