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The intensity level of a sound wave is 4 dB. If the intensity of the wave is doubled, then the intensity level of the sound wave would be [Given $\log_{10} 2 = 0.301$ ]

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detailed solution

Correct option is C

L=10 log10II0∴ L2−L1=10 log10 2II0−10 log10 II0∴L2= L1+10 log102 =4+3 dB=7dB.

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The intensity level of a sound wave is 4 dB. If the intensity of the wave is doubled, then the intensity level of the sound wave would be [Given log102=0.301 ]

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Ready to Test Your Skills?

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The intensity level of a sound wave is 4 dB. If the intensity of the wave is doubled, then the intensity level of the sound wave would be [Given $\log_{10} 2 = 0.301$ ]