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Q.

Intensity of the radiation from the surface of a black body is maximum at a wavelength of 5760A0. If Wien’s constant is 0.288 kelvin-cm. Then the power radiated per unit area of the surface of a black body is

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Detailed Solution

At maximum intensity applying Wien's displacement law,   5760 × T=0.288 × 108 ⇒ T=5000K∴Power radiated per unit surface area σT4=5.67× 10−8 ×(5000)4W/m2=35.4 MW/m2
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