Q.

The intensity of sound increases to 100 times, the level of sound increased by

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a

10 dB

b

20 dB

c

2 db

d

100 dB

answer is A.

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Detailed Solution

β=10log⁡II0& β′=10log100I0I0⇒β′−β=10log10=10dB
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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