First slide
Young's double slit Experiment
Question

In an interference arrangement similar to Young's double slit experiment, the slits S1 and S2 are illuminated with coherent microwave sources each of frequency 106Hz. The sources are synchronized to have zero phase difference. The slits are separated by distance d = 150 m. The intensity I(θ) is measured as a function of θ, where θ is defined as shown. If I0 is maximum intensity, then I(θ) for 0θ90 is given by

Moderate
Solution

For microwave λ=cf=3×108106=300m

 As Δx=dsinθ

Phase difference λ=2πλ (Path difference) 

λ=2πλ(dsinθ)=2π300(150sinθ)=λsinθ

IR=I1+I2+2I1I2cosϕ

 Here I1=I2 and ϕ=πsinθ

   IR=2I1[1+cos(θsinθ)]=4I1cos2πsinθ2

IR will be maximum when cos2πsinθ2=1

 IRmax=4I1=Io

 Hence I=I0cos2πsinθ2

If θ=0, then I=Iocosθ=Io

If θ=30, then I=Iocos2(π/4)=Io/2

If θ=90, then I=Iocos2(π/2)=0

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