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Questions  

In an interference experiment, the ratio of the intensities of the bright and dark fringes is 16.  The ratio of the amplitudes due to the two slits is

a
3 : 1
b
4 : 1
c
5 : 1
d
5 : 3

detailed solution

Correct option is D

The given values are ImaxImin=161 ImaxImin=[I1+I2I1−I2]2=[a1+a2a1−a2]2 ∴[a1+a2a1−a2]2=161       a1+a2a1−a2=41         ⇒a1a2=53

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