Interference fringes are observed on a screen by illuminating two thin slits 1mm apart with a light source λ=632.8 nm. The distance between the screen and the slits is 100cm. If a bright fringe is observed on a screen at a distance of 1.27mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close to:

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2nm

1.27μm

2.87μm

2.05μm

answer is B.

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Detailed Solution

Path difference=dsinθ=d.yD =1mm1.27mm1m=1.27μm